This question was previously asked in

ISRO Scientist Civil 2015 Paper

- \(\frac{P}{2} \cos \theta\)
- \(2P \cos (\frac{\theta }{2})\)
- \(2P \sin (\frac{\theta }{2})\)
- \(\frac{P}{2} \sin \theta\)

Option 2 : \(2P \cos (\frac{\theta }{2})\)

Free

NTPC Diploma Trainee 2020: Full Mock Test

12144

120 Questions
120 Marks
120 Mins

Magnitude of resultant Forces F_{1} and F_{2} is:

\(R=\sqrt{F_1^2+F_2^2+2F_1F_2\cos\theta}\)

F_{1} and F_{2 }= P

\(R=\sqrt{P^2+P^2+2P.P\cos\theta}=\sqrt{2P^2(1+\cos\theta)}=\sqrt{2P^2(2\cos^2\frac{\theta}{2})}=2P\cos\frac{\theta}{2}\)

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,28,76,821+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)